(X^3y^2-3x^2+4y)-(3x^3y^2-x^2y^3+8x-y)=0

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Solution for (X^3y^2-3x^2+4y)-(3x^3y^2-x^2y^3+8x-y)=0 equation: 


Simplifying
(X3y2 + -3x2 + 4y) + -1(3x3y2 + -1x2y3 + 8x + -1y) = 0

Reorder the terms:
(-3x2 + 4y + y2X3) + -1(3x3y2 + -1x2y3 + 8x + -1y) = 0

Remove parenthesis around (-3x2 + 4y + y2X3)
-3x2 + 4y + y2X3 + -1(3x3y2 + -1x2y3 + 8x + -1y) = 0

Reorder the terms:
-3x2 + 4y + y2X3 + -1(8x + -1x2y3 + 3x3y2 + -1y) = 0
-3x2 + 4y + y2X3 + (8x * -1 + -1x2y3 * -1 + 3x3y2 * -1 + -1y * -1) = 0
-3x2 + 4y + y2X3 + (-8x + 1x2y3 + -3x3y2 + 1y) = 0

Reorder the terms:
-8x + -3x2 + 1x2y3 + -3x3y2 + 4y + 1y + y2X3 = 0

Combine like terms: 4y + 1y = 5y
-8x + -3x2 + 1x2y3 + -3x3y2 + 5y + y2X3 = 0

Solving
-8x + -3x2 + 1x2y3 + -3x3y2 + 5y + y2X3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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